By the reaction of carbon and oxygen, a mixture of `CO` and `CO_(2)` is obtained. What is the composition of the mixture by mass obtained when `20` grams of `O_(2)` reacts with `12` grams of carbon ?

Answer

`CO : CO_(2)=21 : 11`

Explanation

`n_(O_(2))=625`
`n_(c)=1` mole
`(n_(O_(2)))/(n_(c))=0.625`
`O_(2)+CrarrCO+CO_(2)`
`2xxn_(O_(2))=n_(CO)+2n_(CO_(2))" "......(I)`
`2xxn_(C)=n_(CO)+n_(CO_(2))" ".....(II)`
`implies (n_(CO)xx28)/(n_(CO_(2))xx44)=(21)/(11)`