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At 100^(@)C and 1 atm, if the density of...

At `100^(@)C` and 1 atm, if the density of the liquid water is `1.0 g cm^(-3)` and that of water vapour is `0.0006 g cm^(-3)` , then the volume occupied by water molecules in `1 L` steam at this temperature is

A

`6cm^(3)`

B

`60cm^(3)`

C

`0.6cm^(3)`

D

`0.06cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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At 100^(@)C and 1 atm , if the density of the liquid water is 1.0 g cm^(-3) and that of water vapour is 0.0006 g cm^(-3) , then the volume occupied by water molecules in 1 L of steam at this temperature is

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Knowledge Check

  • At 100^(@)C and 1 atm. If the density of liquid water is 1.0 g cm^(-3) and that of water vapour is 0.0006 gcm^(-3) , then the volume occupied by water molecules in 1 litre of steam at that temperature

    A
    `6cm^(3)`
    B
    `60cm^(3)`
    C
    `0.6cm^(3)`
    D
    `0.06cm^(3)`

  • The r.m.s. velocity of hydrogen is sqrt(7) times the r.m.s. velocity 1.0 g cm^(-3) and that of wate vapours is 0.0006 g cm^(-3) , then the volume of water molecules in 1 L of steam at this temperature is

    A
    `T(H_(2)) = T(N_(2))`
    B
    `T(H_(2)) gt T(N_(2))`
    C
    `T(N_(2)) gt T(H_(2))`
    D
    `T(H_(2)) = sqrt(7)T(N_(2))`

  • If the density of water is 1 g cm^(-3) then the volume occupied by one molecule of water is approximately

    A
    (a)`18 cm^(3)`
    B
    (b)`22400 cm^(3)`
    C
    (c )`6.02xx10^(-23) cm^(3)`
    D
    (d)`3.0xx10^(-23) cm^(3)`

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