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The pressure of water in a water pipe wh...


The pressure of water in a water pipe when tap is opened and closed is respectively `3xx10^(5)Nm^(-2)` and `3.5xx10^(5)Nm^(-2)` with open tap the velocity of water flowing is
(a). `10m//s`
(b). `5m//s`
(c). `20m//s`
(d). `15m//s`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(open)+(1)/(2)rhov^(2)=P_(closed)impliesV=sqrt((2(P_(closed)-P_(open)))/(rho))=sqrt((2xx(3.5-3)xx10^(5))/(10^(3)))=10m//s`
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