Home
Class 12
PHYSICS
In a YDSE experiment two slits S(1) and ...


In a YDSE experiment two slits `S_(1)` and `S_(2)` have separation of d=2mm the distance of the screen is `D=(8)/(5)` m source S starts moving from a very large distance towards `S_(2)` perpendicular to `S_(1)S_(2)` as shown in figure the wavelength of monochromatic light is 500 n. The number of maximas observed on the screen at point P as the moves towards `S_(2)` is

A

4001

B

3999

C

3998

D

4000

Text Solution

Verified by Experts

The correct Answer is:
D
`S_(1)P-S_(2)P=(d^(2))/(2D)=(2xx10^(-3)xx2xx0^(-3))/(2xx(8)/(5))=(5)/(2)lamda" "(lamda=500nm)`
So when S is at `infty` there is `1^(st)` minima and when S is at `S_(2)` there is last minima because `d//lamda=4000`
So the number of minima's will be 4001 and number of maxima's will be 4000.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WAVE OPTICS

    ALLEN|Exercise Example 9|1 Videos

  • WAVE OPTICS

    ALLEN|Exercise Example 10|1 Videos

  • WAVE OPTICS

    ALLEN|Exercise Example 7|1 Videos

  • UNIT & DIMENSIONS, BASIC MATHS AND VECTOR

    ALLEN|Exercise Exercise (J-A)|7 Videos

Similar Questions

Explore conceptually related problems

In an interference experiment, the two slits S_(1) and S_(2) are not equidistant from the source S. then the central fringe at 0 will be

Two coherent point sources S_(1) and S_(2) vibrating in phase emit light of wavelength lambda . The separation between the sources is 2lambda . Consider a line passing through S_(1) and perpendicular to line S_(1) S_(2) . Find the position of farthest and nearest minima. .

Knowledge Check

  • In the arrangement shown in Fig., slits S_(1) and S_(4) are having a variable separation Z. Point O on the screen is at the common perpendicular bisector of S_(1) S_(2) and S_(3) S_(4) . If a hole is made at O' on AO' O and the slit S_(4) is closed, then the ratio of the maximum to minimum observed on screen at O , if O' S_(3) is equal to (lambda D)/(4d) , is

    A
    1
    B
    infinity
    C
    34
    D
    4

  • Two coherent point sources S_1 and S_2 are separated by a small distance d as shown. The fringes obtained on the screen will be

    A
    points
    B
    straight lines
    C
    semi-circles
    D
    concentric circles

  • In a Young's double-slit experiment, let S_(1) and S_(2) be the two slits, and C be the centre of the screen. If /_S_(1)CS_(2)=theta and lambda is wavelength, the fringe width will be

    A
    `lambda/theta`
    B
    `lambda theta`
    C
    `(2lambda)/theta`
    D
    `lambda/(2theta)`

    • Similar Questions

    Explore conceptually related problems

    Two coherent point sources S_1 and S_2 are separated by a small distance 'd' as shown. The fringes obtained on the screen will be :

    In a Young's double slit experiment, let S_(1) and S_(2) be the two slits, and C be the centre of the screen. If angle S_(1)CS_(2)=theta and lambda is the wavelength, the fringe width will be

    In the arrangement shown in Fig., slits S_(1) and S_(4) are having a variable separation Z. Point O on the screen is at the common perpendicular bisector of S_(1) S_(2) and S_(3) S_(4) . The minimum value of Z for which the intensity at O is zero is

    In a Young's double slit experiment, the slit separation is 1mm and the screen is 1m from the slit. For a monochromatic light of wavelength 500nm , the distance of 3rd minima from the central maxima is

    While conduction the Young's double slit experiment, a student replaced the two slits with a large opaque plate in the x-y plane containing two small holes that act as two coherent point sources (S_(1),S_(2)) emitting light of wavelength 600nm. The student mistakenly placed the screen parallel to the x-z plane (for zgt0) at a distance D=3 m from the mid-point of S_(1) , S_(2) , as shown schematically in the figure. The distance between the sources d=0.6003 mm . The origin O is at the intersection of the screen and the line joining S_(1)S_(2) . Which of the following is (are) true of the intensity pattern of the screen?

    Home
    Profile