The energy levels in a certain single electron species are all `800%` higher in magnitude than corresponding levels of atomic hydrogen. A cartain transition of the electron from the `n^(th)` excited state to the next higher level is possible with a photonn of wavelength `72 nm`. Find the value of `n` .
Given : `((1)/(R) = 90 nm)`

Answer

1

Explanation

Since the energy levels of the species are `9` times the energy levels of hydrogen. The species is `Li^(2+)`.
`(1)/(72) = (1)/(90) (3^(2))((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))`
`rArr (5)/(36) = (1)/(n_(1)^(2)) - (1)/(n_(2)^(2)) rArr n_(1) = 2 , n_(2) = 3`
Hence `n = 2` is first excited state.