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A metal ball of specific gravity 4.5 and...

A metal ball of specific gravity `4.5` and specific heat `0.1 cal//gm-"^(@)C` is placed on a large slab of ice at `0^(@)C`. Half of the ball sinks in the ice. The initial temperature of the ball is:- (Latent heat capacity of ice `=80 cal//g`, specific gravity of ice `=0.9)`

A

`100"^(@)C`

B

`90"^(@)C`

C

`80"^(@)C`

D

`70"^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`V xx 4.5 xx 10^(3) xx 0.1 xx T = (V)/(2) xx 0.9 xx 10^(3) xx 80`
`T = (9 xx 800)/(2xx4.5 xx 11) = 80^(@)C`
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