Home
Class 11
PHYSICS
If y=x lnx "then" (dy)/(dx) will be:...

If `y=x lnx` "then" `(dy)/(dx)` will be:

A

`lnx+x`

B

`1+ln x`

C

`lnx`

D

`1`

Text Solution

AI Generated Solution

The correct Answer is:
To find the derivative of the function \( y = x \ln x \), we can use the product rule of differentiation. The product rule states that if you have a function that is the product of two functions, say \( u \) and \( v \), then the derivative \( \frac{dy}{dx} \) is given by: \[ \frac{dy}{dx} = u \frac{dv}{dx} + v \frac{du}{dx} \] In our case, we can assign: - \( u = x \) - \( v = \ln x \) Now, we will differentiate each part: 1. **Differentiate \( u \)**: \[ \frac{du}{dx} = \frac{d}{dx}(x) = 1 \] 2. **Differentiate \( v \)**: \[ \frac{dv}{dx} = \frac{d}{dx}(\ln x) = \frac{1}{x} \] Now, we can apply the product rule: \[ \frac{dy}{dx} = u \frac{dv}{dx} + v \frac{du}{dx} \] Substituting the values we have: \[ \frac{dy}{dx} = x \cdot \frac{1}{x} + \ln x \cdot 1 \] Now, simplifying this expression: \[ \frac{dy}{dx} = 1 + \ln x \] Thus, the derivative \( \frac{dy}{dx} \) is: \[ \frac{dy}{dx} = 1 + \ln x \] ### Final Answer: \[ \frac{dy}{dx} = 1 + \ln x \] ---

To find the derivative of the function \( y = x \ln x \), we can use the product rule of differentiation. The product rule states that if you have a function that is the product of two functions, say \( u \) and \( v \), then the derivative \( \frac{dy}{dx} \) is given by: \[ \frac{dy}{dx} = u \frac{dv}{dx} + v \frac{du}{dx} \] In our case, we can assign: - \( u = x \) ...
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 2 PHYSICS|1 Videos
  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise DPP NO. 5 Physics|6 Videos
  • CURRENT ELECTRICITY

    RESONANCE|Exercise Exercise|54 Videos
  • ELASTICITY AND VISCOCITY

    RESONANCE|Exercise Advanced Level Problems|9 Videos

Similar Questions

Explore conceptually related problems

If y=(lnx)/(x) "then" (dy)/(dx) will be:

x(dy)/(dx)=y

If y = x/ (x+y) then (dy)/(dx)=

If y = x/(x+y) then (dy)/(dx)=

if y=x^(x) then (dy)/(dx)

If y=a^(a^(x)) then (dy)/(dx)=

If y=x^(x) then (dy)/(dx)=?

if y+x=sin(y+x) then (dy)/(dx)

If y=(x)/(x+y), then (dy)/(dx) =: