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For which of the following graphs the av...

For which of the following graphs the average velocity of a particl moving along a straight line for time interval `(0,t)` must be negative`-`

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D

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To determine which graph indicates that the average velocity of a particle moving along a straight line for the time interval (0, t) must be negative, we need to analyze the concept of average velocity and how it relates to displacement. ### Step-by-Step Solution: 1. **Understanding Average Velocity**: - Average velocity (V_avg) is defined as the total displacement (Δs) divided by the total time (Δt). - Mathematically, it is expressed as: \[ V_{avg} = \frac{\Delta s}{\Delta t} \] 2. **Identifying Displacement**: - Displacement (Δs) is the change in position of the particle from the initial position (s(0)) to the final position (s(t)). - If the final position is less than the initial position, then Δs will be negative. 3. **Analyzing Graphs**: - We need to look for a graph where the position of the particle decreases over the time interval from 0 to t. - This means that the graph should show a downward trend or a slope that is negative. 4. **Graph Interpretation**: - If the graph of position vs. time shows that the particle moves from a higher position to a lower position, the displacement (Δs) will be negative. - Therefore, if Δs is negative and Δt is always positive (since time cannot be negative), the average velocity will also be negative. 5. **Conclusion**: - The graph that shows a downward slope from left to right indicates that the average velocity for the interval (0, t) must be negative.

To determine which graph indicates that the average velocity of a particle moving along a straight line for the time interval (0, t) must be negative, we need to analyze the concept of average velocity and how it relates to displacement. ### Step-by-Step Solution: 1. **Understanding Average Velocity**: - Average velocity (V_avg) is defined as the total displacement (Δs) divided by the total time (Δt). - Mathematically, it is expressed as: \[ ...
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