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A block of mass 20 kg is acted upon by a...

A block of mass 20 kg is acted upon by a force `F=30N` at an angle `53^@` with horizontal in downward direction as shown. The coefficient of friction between the block and the forizontal surface is `0.2`. The friction force acting on the block by the ground is `(g=10(m)/(s^2)`)

A

`40.0N`

B

`30.0N`

C

`18.0N`

D

`44.8N`

Text Solution

Verified by Experts

The correct Answer is:
C
Max. Frictional force
`f_(max)=muN`
`=mu(mg+F sin 53^(@))`
`=0.2(20xx10+30xx(4)/(5))`
`=44.8N`

As applied horizontal force is `F cos 53^(@)`
`=18N lt f_(max)'` friction force will also be `18N`.
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