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The paritcle displacement (in cm) in a s...

The paritcle displacement (in cm) in a stationary wave is given by `y(x,t)=2sin(0.1pix)cos(100pit)`. The distance between a node and the next antinode is

A

`2.5cm`

B

`7.5cm`

C

`5 cm`

D

`10cm`

Text Solution

Verified by Experts

The correct Answer is:
C

`y(x,t)=2 sin (0.1 pix)cos (100pit)`
compare with
`y= A sin (Kx) cos omegat`
`K=0.1pi =(2pi)/(lambda)`
`(pi)/(4)=(20)/(4)=5cm`
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Knowledge Check

  • For a stationary wave y = 10 sin ((pi x)/15) cos (48 pi t) cm, the distance between a node and the nearest antinode is

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  • The equation of a stationary wave is given by y=0.5 cm cos (2pi x) sin (100 pit) . The distance between its successive nodes and antinods is

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    `0.25 cm`
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    C
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    D
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