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A particle is moving with a constant acc...

A particle is moving with a constant acceleration `vec(a) = hat(i) - 2 hat(j) m//s^(2)` and instantaneous velocity `vec(v) = hat(i) + 2 hat(j) + 2 hat(k) m//s` then rate of change of speed of particle 1 second after this instant will be :

A

`sqrt(5) m//s^(2)`

B

`sqrt(3) m//s^(2)`

C

`sqrt(10) m//s^(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
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Knowledge Check

  • A particle is moving with speed 6m//s along the direction of vec(A)=2hat(i)+2hat(j)-hat(k) , then its velocity is :

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    A
    `(4 hat i+2 hatj)`units
    B
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    B
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