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The angles of incidence and refraction o...

The angles of incidence and refraction of a monochromatic ray of light of wavelength `lamda` at an air-glass interface are i and r, respectively. A parallel beam of light with a small spread `delta lamda` in wavelength about a mean wavelength `lamda` is refracted at the same air-glass interface. The refractive index `mu` of glass depends on the wavelength `lamda` as `mu(lamda) = a + b//lamda2` where a and b are constants. Then the angular spread in the angle of refraction of the beam is

A

`|(sin i)/(lamda^(3)cos r)delta lamda|`

B

`|(2b)/(lamda^(3))delta lamda|`

C

`|(2b tan r)/(a lamda^(3) +b lamda)delta lamda|`

D

`|(2b(a+b//lamda^(2))sin i)/(lamda^(3))delta lamda|`

Text Solution

Verified by Experts

The correct Answer is:
C
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According to Cauchy's formula, the refractive index mu of a material is related to wavelength lamda as………. .

The refractive index of a medium ( such as glass) does not depend on the wavelength of light.

Knowledge Check

  • The de-Broglie wavelength lamda

    A
    is proportional to mass
    B
    is proportional to impulse
    C
    Inversely proportional to impulse
    D
    does not depend on impulse

  • Momentum of a photon of wavelength lamda is

    A
    `(h)/(lamda)`
    B
    Zero
    C
    `(h lamda)/(c^(2))`
    D
    `(h lamda)/(c)`

  • Green light of wavelength 5460Å is incident on an air glass interface. If the refractive index of glass is 1.5, the wavelength of light in glass would be (C=3 xx 10^(8) ms^(-1)) n

    A
    `3640Å`
    B
    `5460Å`
    C
    `4861Å`
    D
    `6240Å`

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