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The moment of inertia of a uniform thin ...

The moment of inertia of a uniform thin rod of mass m and length L about two axis PQ and RS passing through centre of rod C and in the plane of the rod are `I_(PQ)` and `I_(RS)` respectively. Then `I_(PQ) +I_(RS)` is equal to

A

`(m l^(2))/(3)`

B

`(ml^(2))/(2)`

C

`(ml^(2))/(4)`

D

`(ml^(2))/(12)`

Text Solution

Verified by Experts

The correct Answer is:
D

The MI of rod about axis PQ figure (a) and MI of rod about axis P'Q' figure (b) are same by symmetry

`:. I_(PQ)+I_(RS)=O_(PQ)+I_(RS)=(ml^(2))/(12)`
by perpendicular axis theorem.
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Knowledge Check

  • Moment of inertia of a thin rod of mass m and length l about an axis passing through a point l/4 from one end and perpendicular to the rod is

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