Home
Class 12
PHYSICS
A shell of mass 4kg moving with a veloco...

A shell of mass `4kg` moving with a velocoity `10m//s` vertically upward explodes into three parts at a height `50m` from ground. After three seconds, one part of mass `2kg` reaches ground and another part of mass `1kg` is at height `40m` from ground. The height of the third part from the ground is : `[g=10m//s^(2)]`

A

50 m

B

80 m

C

100 m

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.58|20 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.59|9 Videos

  • DAILY PRACTICE PROBLEM

    RESONANCE|Exercise DPP No.56|20 Videos

  • CURRENT ELECTRICITY

    RESONANCE|Exercise High Level Problems (HIP)|21 Videos

  • ELECTRO MAGNETIC WAVES

    RESONANCE|Exercise Exercise 3|27 Videos

Similar Questions

Explore conceptually related problems

A body is dropped from a balloon moving up with a velocity of 4 m//s , when the balloon is at a height of 120 m from the ground. The height of the body after 5 s from the ground is:

A metal ball of mass 5 kg falls from a height of 490 m. How much time will it take to reach the ground ? (g=9.8m//s^(2))

A metal ball of mass 5 kg falls from a height of 490 m. How much time will it take to reach the ground ?

A stone of mass 1 kg falls to the earth from a height of 10 m. The kinetic energy of the stone when it is 4 m above the ground is:

What is the work done to fits to lift a body of mass 5 kg to a height of 50 m from the ground (in J)? (g = 10 m s^(-2) )

A body of mass 2 kg is dropped from rest from a height 20 m from the surface of Earth. The body hiys the ground with velocity 10 m/s, then work done (g=10m//s^(2))

A balloon is ringing up with constant velocity of 10 m/s. At a height of 75m a small mass is dropped from it. At what height from the ground would the balloon be when the mass reaches the ground?