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Determine the wavelength of the second l...

Determine the wavelength of the second line of the Paschen series for hydrogen.

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To determine the wavelength of the second line of the Paschen series for hydrogen, we can follow these steps: ### Step 1: Understand the Paschen Series The Paschen series corresponds to transitions of electrons in a hydrogen atom from higher energy levels (n ≥ 4) to the n = 3 energy level. The second line of the Paschen series corresponds to the transition from n = 5 to n = 3. ### Step 2: Use the Rydberg Formula The wavelength of the emitted light during these transitions can be calculated using the Rydberg formula: ...
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Find wavelength of 1^(st) line of Paschen series of hydrogen spectrum.

The wavelength of the first line of the Lyman series of a hydrogen like ion X is identical to that of the second line of the baimer series of another hydrogen like ion Y . Find the ratio of their atomic number.

Knowledge Check

  • The wavelength of the third line of the Balmer series for a hydrogen atom is -

    A
    `(21)/(100R_(H))`
    B
    `(100)/(21 R_(H))`
    C
    `(21R_(H))/(100)`
    D
    `(100R_(H))/(21)`

  • The shortest wavelength of spectral line in Lyman series is 912 Å. The shortest wavelength of the spectral line of the Paschen series is

    A
    8208 Å
    B
    8028 Å
    C
    8828 Å
    D
    8820 Å

  • If the wavelength of the first line of the Balmer series of hydrogen atom is 656.1 nm the wavelngth of the second line of this series would be

    A
    `218.7 nm`
    B
    `328.0 nm`
    C
    `486.nm`
    D
    `640.0nm`

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