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To aqueous solution of Nal, increasing a...

To aqueous solution of `Nal`, increasing amounts of solid `Hgl_(2)`, is added. The vapor pressure of the solution

A

decreases to a constant value

B

increases to a constant value

C

increases first and then decreases

D

remains constant because `Hgl_(2)` is sparingly soluble in water.

Text Solution

Verified by Experts

The correct Answer is:
2
`2Na^(+)(aq)+2I^(-)(aq)+HgI_(2)(g)rarrNa^(+)(aq)+HgI_(4)^(2-)(aq)`
The number of mole particle decrease from `4(2Na^(+)+2I^(-))` to to `3(2Na^(+)+HgI_(4)^(2-))`. Hence, the colligative property will decrease ot, the vapour pressure will increase to a constant value until NaI is completely consumed.
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A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vapourizes to form a more disordered gas. When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas. Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendercy to freeze. In consequence, a lower temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution. The elevation in boiling point (DeltaT_(b)) and depression in freezing point (DeltaT_(f)) of a solution are the colligative properties which depend only on the concentration of particles of the solute and not their identity. For dilute solutions, (DeltaT_(b)) and (DeltaT_(f)) are proportional to the molarity of the solute in the solution. To aqueous solution of Nal , increasing amounts of solid Hgl_(2) is added. The vapour pressure of the solution

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An aqueous solution is 1.00 molal in KI . Which change will cause the vapor pressure of the solution to increase?

An aqueous solution is 1.00 molalin KI. Which change will cause the vapour pressure of the solution to increase ?

Knowledge Check

  • A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vapourizes to form a more disordered gas. When a solute is present, there is additional contribution to the entropy of the liquid due to increased randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas. Thus, a solute (non-volatile) lowers the vapour pressure of a liquid, and hence a higher boiling point of the solution. Similarly, the greater randomness of the solution opposes the tendercy to freeze. In consequence, a lower temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution. The elevation in boiling point (DeltaT_(b)) and depression in freezing point (DeltaT_(f)) of a solution are the colligative properties which depend only on the concentration of particles of the solute and not their identity. For dilute solutions, (DeltaT_(b)) and (DeltaT_(f)) are proportional to the molarity of the solute in the solution. To aqueous solution of Nal , increasing amounts of solid Hgl_(2) is added. The vapour pressure of the solution

    A
    decreases to a constant value
    B
    increases to a constant value
    C
    increases and then decreases
    D
    remains constant as `Hgl_(2)` is sparingly soluble in water

  • The vapour pressure of a solution increases when

    A
    volume is increased
    B
    number of moles of solute is increased
    C
    temperature is increased
    D
    all of these.

  • The vapour pressure of a solution increases when

    A
    The temperature is raised
    B
    the volume is increased
    C
    the number of moles of the solute is increased
    D
    the temperature is lowered
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