If `(x+y)/(0.01)=7`, then `(1)/(2x+2y)=`

Options

A. `0.14`
B. `0.28`
C. `3.50`
D. `7.14`

Explanation

To solve the problem, we need to find the value of \( \frac{1}{2x + 2y} \) given that \( \frac{x+y}{0.01} = 7 \).

### Step-by-Step Solution:

1. **Start with the given equation:**
\[ \frac{x+y}{0.01} = 7 \]

2. **Multiply both sides by \( 0.01 \) to isolate \( x+y \):**
\[ x+y = 7 \times 0.01 \]
\[ x+y = 0.07 \]

3. **Now, we need to find \( \frac{1}{2x + 2y} \). We can factor out the 2 from the denominator:**
\[ 2x + 2y = 2(x+y) \]

4. **Substituting the value of \( x+y \) from step 2:**
\[ 2(x+y) = 2(0.07) = 0.14 \]

5. **Now, substitute this back into the expression we want to evaluate:**
\[ \frac{1}{2x + 2y} = \frac{1}{0.14} \]

6. **Finally, calculate the value:**
\[ \frac{1}{0.14} = \frac{100}{14} = \frac{50}{7} \]

### Final Answer:
\[ \frac{1}{2x + 2y} = \frac{50}{7} \]