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If (x+y)/(0.01)=7, then (1)/(2x+2y)=...

If `(x+y)/(0.01)=7`, then `(1)/(2x+2y)=`

A

`0.14`

B

`0.28`

C

`3.50`

D

`7.14`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of \( \frac{1}{2x + 2y} \) given that \( \frac{x+y}{0.01} = 7 \). ### Step-by-Step Solution: 1. **Start with the given equation:** \[ \frac{x+y}{0.01} = 7 \] 2. **Multiply both sides by \( 0.01 \) to isolate \( x+y \):** \[ x+y = 7 \times 0.01 \] \[ x+y = 0.07 \] 3. **Now, we need to find \( \frac{1}{2x + 2y} \). We can factor out the 2 from the denominator:** \[ 2x + 2y = 2(x+y) \] 4. **Substituting the value of \( x+y \) from step 2:** \[ 2(x+y) = 2(0.07) = 0.14 \] 5. **Now, substitute this back into the expression we want to evaluate:** \[ \frac{1}{2x + 2y} = \frac{1}{0.14} \] 6. **Finally, calculate the value:** \[ \frac{1}{0.14} = \frac{100}{14} = \frac{50}{7} \] ### Final Answer: \[ \frac{1}{2x + 2y} = \frac{50}{7} \]

To solve the problem, we need to find the value of \( \frac{1}{2x + 2y} \) given that \( \frac{x+y}{0.01} = 7 \). ### Step-by-Step Solution: 1. **Start with the given equation:** \[ \frac{x+y}{0.01} = 7 \] ...
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