Write the direction cosines of the line `(x-2)/2=(2y-5)/(-3),\ z=2.`

Explanation

We have given the equations of lines `(x-2)/2=(2y-5)/(-3),\ z=2`

It can be written as

`(x-2)/2=(y-5/2)/(-3/2)=(z-2)/0`

Now the direction ratios of given line are `4, -3, 0`

Hence, direction cosines of the line parallel to AB are proportional to

`4/(sqrt(4^2+(-3)^2+0^2)),-3/(sqrt(4^2+(-3)^2+0^2)),0/(sqrt(4^2+(-3)^2+0^2))`

`=4/5,-3/5,0`