In a competition `A, B` and `C` are participating. The probability that `A` wins is twice that of `B`, the probability that `B` wins is twice that of `C`. find the probability that `A` losses.

Explanation

Given,


`P(A)=2P(B)`


`P(B)=2P(C)`


The events are mutually exhaustive and exclusive


`P(AuuBuuC)=1=P(A)+P(B)+P(C)`


`P(A)+(P(A))/2+(P(A))/4=1`


`P(A)=4/7`


We have to find `P(A')=1-P(A)=1-4/7=3/7`