A random variable X has the following probability distribution: Values of `X :0\ 1\ \ 2\ 3\ \ 4\ 5\ \ 6\ \ 7\ 8` `P(x): a\ 3a\ 5a\ 7a\ \ 9a\ 11 a\ 13 a\ 15 a\ 17 a` Determine: (i). The value of `a` (ii) `P(X<3),\ P(Xgeq3),\ P(0< X < 5)`

Explanation

(i) here the sum of probabilities in a probability distribution is always equal to 1 .



`therefore P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)+P(X=7)+P(X=8)=1 `



`Rightarrow a+3 a+5 a+7 a+9 a+11 a+13 a+15 a+17 a=1 `



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