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Consider the isoelectronic species, Na^(...

Consider the isoelectronic species, `Na^(+),Mg^(2+),F^(-)` and `O^(2-)`. The correct order of increasing length of their radii is:

A

`F^(-) lt O^(2-) lt Mg^(2+) lt Na^(+)`

B

`Mg^(2+) lt Na^(+) lt F^(-) lt O^(2-)`

C

`O^(2-) lt F^(-) lt Na^(+) lt Mg^(2+)`

D

`O^(2-) lt F^(-) lt Mg^(2+) lt Na^(+)`

Text Solution

Verified by Experts

The correct Answer is:
B
Amongst isoelectronic species ionic radii increase as the + ve charge decreases or the negative charge increases. Thus the ionic radii increase in the order `:Mg^(2+) lt Na^(+) lt F^(-) O^(2-)` i.e., option ( b) is correct .
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Knowledge Check

  • The correct order of increasing radii are

    A
    `Be^(2+), Mg^(2+), Na^(o+)`
    B
    `K^(o+), Ca^(2+), S^(2-)`
    C
    `O^(2-), F^(ɵ), N^(3-)`
    D
    `S^(2-), O^(2-), As^(3-)`

  • Consider the isoelectronic species Na^+,Mg^+2,F^-and O^-2 the correct order of their increasing ionic radii is….

    A
    `F^-ltO^-2ltMg^+2ltNa^+`
    B
    `Mg^+2ltNa^+ltF^-ltO^-2`
    C
    `O^-2ltF^-ltNa^+ltMg^+2`
    D
    `O^-2ltF^-ltMg^+2ltNa^+`

  • For Na^(+),Mg^(2+),F^(-) and O^(2-) , the correct order of increasing ionic radii is :

    A
    `Mg^(2+)ltNa^(+)ltF^(-)ltO^(2-)`
    B
    `O^(2-)ltF^(-)ltNa^(+)ltMg^(2+)`
    C
    `Na^(+)ltMg^(2+)ltF^(-)ltO^(2-)`
    D
    `Mg^(2+)ltO^(2-)ltNa^(+)ltF^(-)`

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