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The standard reduction potentials of Cu^...

The standard reduction potentials of `Cu^(2+)//Cu` and `Cu^(2+)//Cu^(+)` are 0.337 V and 0.153V respectively. The standard electrode potential of `Cu^(+)//Cu` half-cell is

A

1.184V

B

0.827V

C

0.521V

D

0.490V

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The correct Answer is:
To find the standard electrode potential of the half-cell reaction `Cu^+ // Cu`, we can use the given standard reduction potentials for the half-cells `Cu^2+ // Cu` and `Cu^2+ // Cu^+`. ### Step-by-Step Solution: 1. **Identify the Given Potentials**: - The standard reduction potential for `Cu^2+ + 2e^- → Cu` is \( E_1 = 0.337 \, V \). - The standard reduction potential for `Cu^2+ + e^- → Cu^+` is \( E_2 = 0.153 \, V \). 2. **Write the Reactions**: - For the first reaction: \[ Cu^{2+} + 2e^- \rightarrow Cu \quad (E_1 = 0.337 \, V) \] - For the second reaction: \[ Cu^{2+} + e^- \rightarrow Cu^+ \quad (E_2 = 0.153 \, V) \] 3. **Determine the Reaction for `Cu^+ // Cu`**: - We want to find the standard reduction potential for the reaction: \[ Cu^+ + e^- \rightarrow Cu \quad (E_3) \] 4. **Use Gibbs Free Energy Relationship**: - The Gibbs free energy change for a reaction is related to the standard electrode potential by the equation: \[ \Delta G = -nFE \] - For the first reaction (2 electrons), the Gibbs free energy change is: \[ \Delta G_1 = -2F \cdot E_1 = -2F \cdot 0.337 \] - For the second reaction (1 electron), the Gibbs free energy change is: \[ \Delta G_2 = -1F \cdot E_2 = -1F \cdot 0.153 \] 5. **Combine the Reactions**: - To find \( E_3 \), we can use the relationship: \[ \Delta G_3 = \Delta G_1 - \Delta G_2 \] - Substituting the Gibbs free energy changes: \[ \Delta G_3 = (-2F \cdot 0.337) - (-1F \cdot 0.153) \] - Simplifying gives: \[ \Delta G_3 = -2F \cdot 0.337 + F \cdot 0.153 \] 6. **Calculate \( E_3 \)**: - Since \( \Delta G_3 = -F \cdot E_3 \), we can set up the equation: \[ -F \cdot E_3 = -2F \cdot 0.337 + F \cdot 0.153 \] - Dividing through by \( -F \) (and canceling \( F \)): \[ E_3 = 2 \cdot 0.337 - 0.153 \] - Now calculate: \[ E_3 = 0.674 - 0.153 = 0.521 \, V \] 7. **Final Answer**: - The standard electrode potential for the half-cell reaction `Cu^+ // Cu` is \( E_3 = 0.521 \, V \).
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Knowledge Check

  • The standard reduction potentials of Cu^(2+)//Cu and Cu^(2+)// Cu^(+) are 0.337 V and 0.153 V respectively. The standard electrode potential of Cu^(+)//Cu half cell is:

    A
    `0.184` V
    B
    `0.827` V
    C
    `0.521` V
    D
    `0.490` V
  • The standard reduction potentials for Cu^(2+)//Cu and Cu^(2+)//Cu^(+) are 0.337 V and 0.153 V respectively. The standard electrode potenials of Cu^(+)//Cu half cell is :

    A
    `0.184 V`
    B
    `0.827 V`
    C
    `0.521V`
    D
    `0.490 V`
  • The standard reduction potential of Cu^(2+)//Cu and Cu^(2+)//Cu^(+) are 0.339 V and 0.153 V respectively. The standard electrode potential of Cu^(+)//Cu half cell is :

    A
    `0.525 V`
    B
    `0.827 V`
    C
    `0.184 V`
    D
    `0.490 V`
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