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At 323 K, the vapour pressure in millime...

At 323 K, the vapour pressure in millimeters of mercury of a methanol - ethanol solution is represented by the equation` p=120X_(A)+140, ` where `X_(A)` is the mole fraction of methanol. Then the value of `underset(x_(A)rarr1)"lim"(p_(A))` is :

A

`250mm`

B

`140mm`

C

`260mm`

D

`20mm`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • At 323 K, the vapour pressure in millimeters of mercury of a methanol - ethanol solution is represented by the equation p=120X_(A)+140, where X_(A) is the mole fraction of methanol. Then the value of underset(x_(A)rarr1)"lim"(p_(A))/(p_(B)) is :

    A
    250mm
    B
    140mm
    C
    260mm
    D
    20mm

  • At 40^(@)C , the vapour pressures in torr, of methyl alcohol and ethyl alcohol solutions is represented by the equation. P = 119X_(A) + 135 where X_(A) is mole fraction of methyl alcohol, then the value of underset(x_(A)rarr1)(lim)(P_(A))/(X_(A)) is

    A
    254 torr
    B
    135 torr
    C
    119 torr
    D
    140 torr

  • Vapour pressure of methyl alcohol and ethyl alcohol solutions is represented by P = 115 x_(A)+140 where x_(A) is the mole fraction of methyl alcohol. The value of underset(x_(A)rarr0)(lim)(P_(B)^(0))/(x_(B)) is:

    A
    255
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    C
    140
    D
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    At a given temperature, the vapour pressure in mm of Hg of a solution of two volatile liquids A and B is given by the equation p=120-80X_(B)(X_(B)="mole fraction of B") Calculate the vapour pressures of pure A and B at the same temperature.

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