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At 323 K, the vapour pressure in millime...

At 323 K, the vapour pressure in millimeters of mercury of a methanol - ethanol solution is represented by the equation` p=120X_(A)+140, ` where `X_(A)` is the mole fraction of methanol. Then the value of `underset(x_(A)rarr1)"lim"(p_(A))` is :

A

`250mm`

B

`140mm`

C

`260mm`

D

`20mm`

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The correct Answer is:
C
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At 323 K, the vapour pressure in millimeters of mercury of a methanol - ethanol solution is represented by the equation p=120X_(A)+140, where X_(A) is the mole fraction of methanol. Then the value of underset(x_(A)rarr1)"lim"(p_(A))/(p_(B)) is :

At 40^(@)C , the vapour pressures in torr, of methyl alcohol and ethyl alcohol solutions is represented by the equation. P = 119X_(A) + 135 where X_(A) is mole fraction of methyl alcohol, then the value of underset(x_(A)rarr1)(lim)(P_(A))/(X_(A)) is

Vapour pressure of methyl alcohol and ethyl alcohol solutions is represented by P = 115 x_(A)+140 where x_(A) is the mole fraction of methyl alcohol. The value of underset(x_(A)rarr0)(lim)(P_(B)^(0))/(x_(B)) is:

At 40^(@)C , the vapour pressure in torr of methyl and ethyl alcohol solutions is represented by P = 119 X_(A)+135 , where X_(A) is mole fraction of methyl alcohol. The value of (P_(B)^(@))/(X_(B)) at lim X_(A) rarr 0) , and (P_(A)^(@))/(X_(A)) at lim X_(B) rarr 0 are:

At 40^(@)C , vapour pressure in Torr of methanol nd ethanol solution is P=119x+135 where x is the mole fraction of methanol. Hence

At 40^(@)C , vapour pressure in torr of methanol and ethanol solution is P=119x+135, where x is the mole fraction of methanol. Hence :

RESONANCE-SOLUTIONS-EXERCISE-2(PART-2)
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