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Two small balls having the same mass and...

Two small balls having the same mass and charge and located on the same vertical at heights `h_(1)` and `h_(2)` are thrown in the same direction along the horizontal at the same velocity v. The first ball touches the ground at a horizontal distance R from the initial vertical position. At what height `h_(2)` will the second ball be at this instant? Neglect any frictional resistance of air and the effect of any induced charge on the ground.

Text Solution

Verified by Experts

The correct Answer is:
`H_(2)=h_(1)+h_(2)-g(l/v)^(2)`

Time to fall first ball
`t=l/v :. h_(1)=1/2xxgxxl^(2)/v^(2)`
`:.` Height of 2nd ball
`=h_(2)-1/2gl^(2)/v^(2)`
`pr=h_(2)+1/2 g l^(2)/v^(2), h_(2)+h_(1)-g (l^(2)/v^(2))`
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