A perpendicular drawn from a vertex to the opposite side of a triangle is known as an altitude     (b) a median        (c)  an angle bisector a bisector

Altitudes the perpendiculars drawn from the vertices of a trriangle to the opposite side are known as the altitudes of the triangle.

Line segments joining the vertices to the mid- points of the opposite sides to a triangle are known as medians (b) altitudes (c) heights (d) angle bisectors

Consider the following statements : 1. The point of intersection of the perpendicular bisectors of the sides of a triangle may lie outside the triangle. 2. The point of intersection of the perpendiculars drawn from the vertices to the opposite sides of a triangle may lie on two sides. Which of the above statements is/are correct ?

Show that the perpendicular bisectors of the sides of a triangle are concurrent.

Prove that the sum of three altitudes drawn from the vertices to opposite sides of a triangle is less than the sum of three sides. or Prove that the perimeter of a triangle is greater than the sum of three altitudes drawn from the vertices to opposite of a triangle.

Line joining the mid-point of a side of a triangle to opposite vertex is Median

In /_ABC, perpendicular BE is drawn from vertex B on internal angle bisector from vertex A such that it divide /_B in 1:2 (point E lies on internal angle bisector from vertex A and lies inside Delta ABC) and Delta ABE is isoceless,then value of /_C will be

If the altitude from one vertex of a triangle bisects the opposite side; then the triangle is isosceless.