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Two forces F(1) and F(2) are acting on a...

Two forces `F_(1)` and `F_(2)` are acting on a body. One force is double that of the other force and the resultant is equal to the greater force. Then the angle between the two forces is

A

`cos^(-1)(1//2)`

B

`cos^(1)(-1//2)`

C

`cos^(-1)(-1//4)`e

D

`cos^(-1)(1//4)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the angle between two forces \( F_1 \) and \( F_2 \) given that one force is double the other and the resultant is equal to the greater force. Let's break it down step by step. ### Step 1: Define the Forces Let: - \( F_1 \) be the smaller force. - \( F_2 = 2F_1 \) be the greater force (since one force is double the other). ### Step 2: Write the Resultant Force Equation According to the problem, the resultant force \( R \) is equal to the greater force \( F_2 \): \[ R = F_2 = 2F_1 \] ### Step 3: Use the Formula for Resultant of Two Forces The formula for the resultant \( R \) of two forces \( F_1 \) and \( F_2 \) acting at an angle \( \theta \) is given by: \[ R = \sqrt{F_1^2 + F_2^2 + 2F_1F_2 \cos \theta} \] Substituting \( F_2 = 2F_1 \) into the equation: \[ R = \sqrt{F_1^2 + (2F_1)^2 + 2F_1(2F_1) \cos \theta} \] This simplifies to: \[ R = \sqrt{F_1^2 + 4F_1^2 + 4F_1^2 \cos \theta} \] \[ R = \sqrt{5F_1^2 + 4F_1^2 \cos \theta} \] ### Step 4: Set the Resultant Equal to the Greater Force Since we know \( R = 2F_1 \), we can set the two expressions equal to each other: \[ 2F_1 = \sqrt{5F_1^2 + 4F_1^2 \cos \theta} \] ### Step 5: Square Both Sides To eliminate the square root, we square both sides: \[ (2F_1)^2 = 5F_1^2 + 4F_1^2 \cos \theta \] \[ 4F_1^2 = 5F_1^2 + 4F_1^2 \cos \theta \] ### Step 6: Rearrange the Equation Rearranging gives us: \[ 4F_1^2 - 5F_1^2 = 4F_1^2 \cos \theta \] \[ -F_1^2 = 4F_1^2 \cos \theta \] ### Step 7: Solve for \( \cos \theta \) Dividing both sides by \( F_1^2 \) (assuming \( F_1 \neq 0 \)): \[ -1 = 4 \cos \theta \] \[ \cos \theta = -\frac{1}{4} \] ### Step 8: Find the Angle \( \theta \) To find \( \theta \), we take the inverse cosine: \[ \theta = \cos^{-1}\left(-\frac{1}{4}\right) \] ### Conclusion The angle between the two forces \( F_1 \) and \( F_2 \) is \( \theta = \cos^{-1}\left(-\frac{1}{4}\right) \).
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