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The work function for cesium is 1.8 eV. ...

The work function for cesium is 1.8 eV. A light of wavelength `5000 Å` is incident on it. Calculate (i) maximum kinetic energy of emitted electrons, (ii) threshold frequency and threshold wavelength and (iii) maximum velocity of the emitted electrons

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(i) `1.08 xx 10^(-19)J`, (ii) `4.363 xx 10^(14)Hz, 6.875 xx 10^(-7)m`, (iii) `4.9 xx 10^(5) m.s^(-1)`
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Knowledge Check

  • The work function of a metal surface is 2.0 eV. Light of wavelength 5000 Å is incident on it:

    A
    the energy of each incident photon is 2.48 eV
    B
    the threshold wavelength for photoelectric effect is `6200 Å`
    C
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    D
    stopping potential is 0.48 eV

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    A
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    B
    photoelectrons will be emitted from both the metals
    C
    maximum kinetic energy of the photoelectron will be higher in metal B
    D
    threshold wavelength of photoelectric effect in case of metal A will be `4000 Å` approximately

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