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Statement I: Any light wave having frequ...

Statement I: Any light wave having frequency less than `4.8 xx 10^(14)Hz` cannot emit photoelectrons from a metal surface having work function 2.0 eV
Statement II: If the work function of a metal is `W_(0)` (in eV), then the maximum wavelength (in `Å`) of the light capable of initiating photoelectric effect in the metal is given by `lamda_("max") = (12400)/(W_(0))`

A

Statement I is true, statement II is true, statement II is a correct explanation for statement I

B

Statement I is true, statement II is true, statement II is not a correct explanation for statement I

C

statement I is true, statement II is false

D

statement I is false, statement II is true

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The work function of a metal surface is 2.0 eV. Light of wavelength 5000 Å is incident on it:

    A
    the energy of each incident photon is 2.48 eV
    B
    the threshold wavelength for photoelectric effect is `6200 Å`
    C
    maximum kinetic energy of emitted photoelectron is 0.48 eV
    D
    stopping potential is 0.48 eV

  • When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased from 0.5eV to 0.8eV. The work function of the metal is

    A
    0.65 eV
    B
    1.0 eV
    C
    1.3 eV
    D
    1.5 eV

  • The work function of metals is in the range of 2 eV to 5 eV. Find which of the following wavelength of light cannot be used for photoelectric effect. (Consider, Planck's constant = 4 xx 10^(-15) eV.s , velocity of light = 3 xx 10^(8) m//s )

    A
    510 nm
    B
    650 nm
    C
    400 nm
    D
    570 nm

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    Calculate the threshold frequency of photon for photoelectric emission from a metal of work function 0.1eV.

    Threshold wavelength for photoelectric emission from a metal surface is 3800Å , Utraviolet light of wave-length 2600Å is incident on the metal surface. Find the work function of the metal and

    A photon of wavelength 4x10^-7 m strikes a metal surface work function of the metal is 2.13eV calculate the kinetic energy of the emitted photoelectrons in eV

    Work function for a metal is 1.77 eV and the wavelength of an incident ray on that metal is 5893 Å . Determine the maximum kinetic energy of the photoelectrons emitted from that metal.

    A metal surface does not emit any electron if the energy of incident radiation is less than the photoelectric work function of the metal - justify the statement mathematically.

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