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An equilibrium system for the reaction b...

An equilibrium system for the reaction between hydrogen and iodine to give hydrogen iodide at 765 K in a 5 litre volume contains 0.4 mole of hydrogen, 0.4 mole of iodine and 2.4 moles of hydrogen iodide, The equilibrium constant for the reaction is :
`H_2+I_2 hArr 2HI`, is :

A

`36.0`

B

`15.0`

C

`0.067`

D

`0.28`

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The correct Answer is:
A
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Knowledge Check

  • An equilibrium system for the reaction between hydrogen and iodien to give hydrogen iodide at 765 K in a 5 litre volume contains 0.4 mole of hydrogen iodide. The equilibrium constant for the reaction H_(2) + I_(2)hArr 2HI is

    A
    `36.0`
    B
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    C
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    D
    `0.028`

  • 1.50 moles each of hydrogen and fodine were placed in sealed 10 litre container maintained ar 717 K At eqinlibrium 1.25 moles each of hydrogen and iodine were left behind The equilibrium constant, K for the reaction. H_2(g) +I_2(g) harr 2HI(g) at 717 K is

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    0.4
    B
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    C
    25
    D
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  • On a given condition, the equilibrium concentration of H, H_(2) and I_(2) are 0.80 , 0.10 and 0.10 mole/litre. The equilibrium constant for the reaction H_(2) + I_(2) hArr 2HI will be

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