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The degree of dissociation of SO(3) at e...

The degree of dissociation of `SO_(3)` at equilibrium pressure is alpha : `K_(p)` for `2SO_(3) (g)hArr2SO_(2)(g) + O_(2) (g)`

A

`[((P_0alpha^3))/(2(1-alpha)^3)]`

B

`[((P_0alpha^3))/((2+alpha)(1-alpha)^2)]`

C

`[((P_0alpha^3))/(2(1-alpha)^2)]`

D

None of these

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The degree of dissociation of SO_(3) at equilibrium pressure is: K_(p) for 2SO_(3) (g)hArr2SO_(2)(g) + O_(2) (g)

    A
    `[(P_(0)alpha^(3))//2(1 - alpha)^(3)]`
    B
    `[(P_(0)alpha^(3))//(2 + alpha)(1 - alpha)^(2)]`
    C
    `[(P_(0)alpha^(2))//2(1 - alpha)^(2)]`
    D
    None of these

  • At equilibrium degree of dissociation of SO_(3) is 50% for the reaction 2SO_(3)(g)hArr 2SO_(2)(g)+O_(2)(g) . The equilibrium constant for the reaction is

    A
    0.15
    B
    0.25
    C
    2.5
    D
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  • Identify the correct statement for SO_(3) (g) hArr SO_(2) (g) + (1)/(2) O_(2) (g)

    A
    On increasing temperature at equilibrium, reaction will move in backward direction
    B
    On increasing pressure reaction will move in backward direction
    C
    Catalyst will alter equilibrium concentration of reactants and products
    D
    both (1) and (2) are correct

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