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Equal weight of CH(4) and H(2) are mixed...

Equal weight of `CH_(4) and H_(2)` are mixed in an empty container at `25^(@)C`. The fraction of the total pressure exerted by `H_(2)` is-

A

`1/9`

B

`1/2`

C

`8/9`

D

`(16)/(17)`

Text Solution

Verified by Experts

The correct Answer is:
C
Gas mixture contains equal masses of `CH_(4) and H_(2)`. ltBrgt So, in the mixture, `n_(H_(2))=(w)/(2)mol,n_(CH_(4))=(w)/(16)` mol
`x_(H_(2))=(w//2)/((w)/(2)+(w)/(16))=(8)/(9) and x_(CH_(4))=1-x_(H_(2))=1-(8)/(9)=(1)/(9)`
`therefore`The partial presure of `H_(2),p_(H_(2))=x_(H_(2))xxP=(8)/(9)P`
[P=total pressure of the mixture]
`therefore (p_(H_(2)))/(P)=(8)/(9)`
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Knowledge Check

  • Equal masses of CH_4 and O_2 are mixed in an empty container at 25^@C . The fraction of the total pressure exerted by O_2 is ?

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