Home
Class 11
CHEMISTRY
0.1 ATM=Pa=torr....

0.1 ATM=_____Pa=_______torr.

Text Solution

Verified by Experts

`1.013xx10^(4)`, 76.
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise EXERCISE (SHORT TYPE QUESTIONS)|31 Videos

  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise EXERCISE (NUMBERICAL PROBLEMS)|56 Videos

  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise EXERCISE (VERY SHORT TYPE QUESTIONS)|24 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    CHHAYA PUBLICATION|Exercise PRACTICE SET|13 Videos

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise PRACTICE SET|15 Videos

Similar Questions

Explore conceptually related problems

1 Pa.s =_____

1 mmHg= ?___ torr ?

1 atm = ?___mmHg.

1 torr = ________ dyn*cm^(-2) [Fill in the blank]

1 atm = ?___ cmHg.

At a constant temperature, the pressures of four gases A, B, C, D are 0.2 atm, 250 torr, 26.23 kPa and 14.2 bar, rspectively. Arrange them according to their increasing pressure.

What is torr?

The vapour pressure of a liquid solution containing A and B is 99 torr. Calculate mole % of B in vapour phase. (Given : P_A^0 = 100 torr , P_B^0 = 80 torr)

At 518^(@)C , the rate od decomposition of a sample of gaseous acetaldehyde, initially at a pressure of 363 torr, was 1.00 torr. s^(-1) when 5% had reacted and 0.5 "torr".s^(-1) when 33% had reacted. The order of the reaction is -

The vapour pressure of acetone at 20^@C is 185 torr. When 1.2 g of a non-volatile solute was dissolved in 100 g of acetone at 20^@C its vapour pressure was 183 torr. The mass (g mol^(-1)) of the substance is.

Knowledge Check

  • At 518^(@)C , the rate od decomposition of a sample of gaseous acetaldehyde, initially at a pressure of 363 torr, was 1.00 torr. s^(-1) when 5% had reacted and 0.5 "torr".s^(-1) when 33% had reacted. The order of the reaction is -

    A
    1
    B
    0
    C
    2
    D
    3

  • The vapour pressure of acetone at 20^@C is 185 torr. When 1.2 g of a non-volatile solute was dissolved in 100 g of acetone at 20^@C its vapour pressure was 183 torr. The mass (g mol^(-1)) of the substance is.

    A
    64
    B
    128
    C
    488
    D
    32