The volume of 50 g of a substance is `20cm^(3).` If the density of water is `1g//cm^(3)`, will the substance sink or float when placed on the surface of water will be the mats of water dispaced by the substance ?

Explanation

`"Density of the substance"=("Mass")/("volume")=(50)/(20)=2.5g//cm^(3)`
`"Density of water"=1gm//cm^(3)`
Density of the substance gt Density of water
Relative of the substance `=(2.5gm//cm^(3))/(1gm//cm^(3))=2.5`
`"Relative density of the substance"=("Weight of the substance")/("Weight of the water equal to the volume of the substance")`
`2.5=(50)/(x)rArrx=(50)/(2.5)=20g`
`therefore` Weight of the water displaced by the substance = 20 g