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Two bodies (M) and (N) of equal masses a...

Two bodies (M) and (N) of equal masses are suspended from two separate massless springs of spring constants (k_1) and (k_2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of (M) to the of (N) is.

A

` k_(1)/k_(2)`

B

` sqrt(k_(1)/k_(2))`

C

` k_(2)/k_(1)`

D

` sqrt(k_(2)/k_(1))`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Two bodies A and B of equal mass are suspended from two separate massless springs of spring constant k_1 and k_2 respectively. If the bodies iscillte vertically such that their maxixum velocities are equal, the ratio of the amplitude of A to that of B is

    A
    `k_1/k_2`
    B
    `sqrt(k_1/k_2)`
    C
    `k_2/k_1`
    D
    `sqrt(k_2/k_1)`
  • Two bodies P and Q of equal masses are suspended from two separate massless springs of force constants k_(1) and k_(2) respectively. If the two bodies oscillate vertically such that their maximum velocities are equal. The ratio of the amplitude of P to that of Q is

    A
    `sqrt((k_(1))/(k_(2))`
    B
    `(k_(1))/(k_(2))`
    C
    `sqrt((k_(2))/(k_(1)))`
    D
    `(k_(2))/(k_(1))`
  • Two particles (A) and (B) of equal masses are suspended from two massless spring of spring of spring constant k_(1) and k_(2) , respectively, the ratio of amplitude of (A) and (B) is.

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    (a) `sqrtk_(1_/k_(2_`
    B
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    C
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    D
    (d) k_(1)/k_(2)`
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