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Two solutions of a substance (non-electr...

Two solutions of a substance (non-electrolyte) are mixed in the following manner , 480 mL of 1.5 M [first solution ] + 520 mL of 1.2 M [second solution ] . What is the molarity of the final mixture ?

A

1.20 M

B

1.50M

C

1.344 M

D

2.70 M

Text Solution

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The correct Answer is:
C
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Two solutions of a substances (non-electrolyte) are mixed in the manner, 480 mL of 1.5 M of first solution with 250 mL of 1.2 M of second solution.

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Knowledge Check

  • Two solution of a substance (non-electroyte ) are mixed in the following manner : 480 mL of 1.5 M first solution + 520 mL of 1.2 M second solution . What is the molarity of the final mixture ?

    A
    `1.20 M`
    B
    `1.50M`
    C
    `1.344M`
    D
    `2.70M`

  • Two solutions of a substance (non-electrolyte) are mixed in the following manner. 480 mL of 1.5M first solution +520 mL of 1.2M second solution. What is the molarity of the final mixture?

    A
    `1.20M`
    B
    `1.50M`
    C
    `1.344 M`
    D
    `2.70M`

  • Two solutions of a substances (non electrolyte) are mixed in the following manner. 480 ml of 1.5M first solution +520 mL of 1.2M second solution. What is the molarity of the final mixture?

    A
    `1.50M`
    B
    `1.20M`
    C
    `2.70M`
    D
    `1.344M`

    • Similar Questions

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    Two solutions of a substance (non-electroyte) are mixed in the following manner 480 mL of 1.5M of first solution with 520 mL or 1.2M of second solution. The molarity of final solution is:

    200 mL of water is added to 500 mL of 0.2 M solution. What is the molarity of the diluted solution ?

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    200 ml of water is added to 500 ml of 0.2 M solution. What is the molarity of this diluted solution

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