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A collimated beam of light of flux densi...

A collimated beam of light of flux density `30kWm^(-2)` is incident normally on `100mm^(2)` completely absorbing screen. If P is the pressure exerted on the screen and `trianglep` is the momentum tranferred to the screen during a 1000 s interval, then

A

`P = 10^(-3)Nm^(-2)`

B

`P = 10^(-4)Nm^(-2)`

C

`Deltap = 10^(-4)kgms^(-1)`

D

`Deltap = 10^(-5)kgms^(-1)`

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Knowledge Check

  • Light is incident normally on a completely absorbing surface with an energy flux of 25 Wcm^(-2) If the surface has an area of 25 cm^(2) the momentum transferred to the surface in 40 min time duration will be:

    A
    `6.3 xx 10^(-4) Ns`
    B
    `5.0 xx 10^(-3) Ns`
    C
    `1.4 xx 10^(-6) Ns`
    D
    `3.5 xx 10^(-6) Ns`
  • A parallel beam of light of wavelength 600 nm is incident normally on a slit of width d. If the distance between the slits and the screen is 0.8 m and the distance of 2^(nd) order maximum from the centre of the screen is 15 mm. The width of the slit is

    A
    `40 mu m`
    B
    `80 mu m`
    C
    `160 mu m`
    D
    `200 mu m`
  • Light of wavelength 6328 Å is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :

    A
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    B
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    C
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    D
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