The hydrogen ATOMS are excited to n=3 . During de-excitation, whatever photons are emitted are being used to eject photoelectrons from a metal surface. What should be the maximum work function.of the metal (in eV ) so that the photon of minimum energy can also eject photoelectron from the metal?

Wavelengths belonging to Balmer series lying in the range of 450 nm to 750 nm were used to eject photoelectrons from a metal surface whose work function is 2.0 eV. Find ( in eV ) the maximum kinetic energy of the emitted photoelectrons. ("Take hc = 1242 eV nm.")

Wavelength belonging to Balmer series lying in the range of 450 nm to 750 nm wer used to eject photoelectrons from a metal surface whose work functiion is 2.0eV. Find (in eV) the maximum kinetic energy of the emitted photoelectrons. (Take hc =1242eV nm).

Light of wavelength 4000 Å is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface ?

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

The threshold wavelength for emission of photoelectrons from a metal surface is 6xx10^(-7)m .The work function of the material of the metal surface is.

The surface of a metal illuminated with the light of 400 nm . The kinetic energy of the ejected photoelectrons was found to be 1.68 eV . The work function of the metal is : (hc=1240 eV.nm)