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A radioactive element .90 X^238 decay in...

A radioactive element `._90 X^238` decay into `._83 Y^222`. The number of `beta-`particles emitted are.

A

4

B

6

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • A radioactive element ""_(90)X^(238) decays into ""_(83)Y^(222) . The number of beta -particular emitted are :

    A
    4
    B
    6
    C
    2
    D
    1

  • A radioactive nucleus ._92 X^235 decays to ._91 Y^231 . Which of following particles are emitted ?

    A
    One alpha and one electron
    B
    Two deutrons and one position
    C
    One alpha and one proton
    D
    One proton and four neutrons

  • In the nuclear reaction U_92^238 to Pb_82^206 , the number of alpha and beta particles decayed are:

    A
    `4 alpha, 3 beta`
    B
    `8alpha, 6beta`
    C
    `6alpha,4beta`
    D
    `7alpha,5beta`

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