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In Fig. ABCDEF is a ragular hexagon. Pro...

In Fig. ABCDEF is a ragular hexagon. Prove that
`vec(AB) +vec(AC) +vec(AD) +vec(AE) +vec(AF) = 6 vec(AO)`.

Answer

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Knowledge Check

  • ABCDEF is a regular hexagon with point O as centre. The value of vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF) is

    A
    `2vec(AO)`
    B
    `2vec(AO)`
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    `6vec(AO)`
    D
    0

  • If ABCDEF is a regular hexagon , then A vec D + E vec B + F vec C equals

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    ` 2 A vec B `
    B
    `vec 0`
    C
    `3 A vec B `
    D
    `4 A vec B `

  • If ABCDE is a pentagon, then vec(AB) + vec(AE) + vec(BC) + vec(DC) + vec(ED) + vec(AC) is equal to

    A
    `4 vec(AC)`
    B
    `2 vec(AC)`
    C
    `3vec(AC)`
    D
    `5 vec(AC)`

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    ABCDE is a pentagon prove that vec(AB)+vec(BC)+vec(CD)+vec(DE)+vec(EA)=vec0

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