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If the dimensions of B^(2)l^(2)C are [M^...

If the dimensions of `B^(2)l^(2)C` are `[M^(a)L^(b)T^(c)]`, then the value of `a+b+c` is
[Here `B,l` and `C` represent the magnitude of magnetic field, length and capacitance respectively]

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Knowledge Check

  • If the dimensions of a physical quantity are given by M^(a)L^(b) T^(c) , then the physical quantity will be

    A
    velocity if a 1, b = 0, c =-1
    B
    acceleration if a = 1, b= 1, c = -2
    C
    force if a = 0, b = - 1, c = - 2
    D
    pressure if a = 1, b =-1, c = -2

  • If the dimensions of a physical quantity are given by M^(a)L^(b)T^(c) , then the physical quantity will be :

    A
    Force if `a = 0, b = –1, c = – 2 `
    B
    Pressure if `a = 1, b = – 1, c = – 2 `
    C
    Velocity if `a = 1, b = 0, c = – 1`
    D
    Acceleration if `a = 1, b = 1, c = – 2`

  • If the dimensions of a physical quantity are given by [L^(a),M^(b)T^(c)] ,then the physical quantity will be

    A
    force ,if a = -1 , b=0,c=- 2
    B
    pressure, if a=-1,b=1,c=-2
    C
    velocity , if a =1, b=0,c=1
    D
    acceleration , if a=1,b=1,c=2

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    The dimension of magnetic field in M,L,T and C (coulomb) is given as

    If the dimension of a physical quantity are given by M^a L^b T^c, then the physical quantity will be

    The quantities RC and (L/R) (where R, L and C stand for resistance, inductance and capacitance respectively) have the dimension of

    The dimension of magnetic field in M, L, T and C (Colulomb) is given as

    The dimension of magnetic field in M, L, T and C (Coulomb) is given as :

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