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A motor car tyre is pumped up to pressur...

A motor car tyre is pumped up to pressure of two atmosheres at `15^(@)C` when it suddenly bursts. Calculate the resulting drop in temperature of the escaping air `(gamma =14)`.

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A motor car tyre has a pressure of 2 atmosphere at room temperature of 27^(@)C . If the tyre suddenly bursts, find the resulting temperature (in kelvin).

A tyre pumped to a pressure of 6 atmosphere, suddenly bursts. Room temperature is 15^circ C . Calculate the temperature of escaping air gamma= 1.4 .

Knowledge Check

  • A motor car type has a pressure of 2 atmosphere at 27^(@)C . It suddenly burts. If C_(P)//C_(V) = 1.4 for air, then the resulting temperature is

    A
    27 K
    B
    `27^(@)C`
    C
    `-27^(@)C`
    D
    `246^(@)C`

  • A tyre pumped to a pressure 3.375 atm "at" 27^(@)C suddenly bursts. What is the final temperature (gamma = 1.5) ?

    A
    `27^(@)C`
    B
    `-27^(@)C`
    C
    `0^(@)C`
    D
    `-73^(@)C`

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    Explore conceptually related problems

    A tyre pumped to a pressure of 6 atmosphere suddenly bursts. Room temperature is 25^(@)C . Calculate the temperature of escaping air. (gamma=1.4.)

    A tyre pumped to a pressure of 3.375 atmosphere and at 27^@C suddenty bursts. What is the final temperature ? (gamma = 1.5)

    A tyre pumped to a pressure of 6 atmosphere bursts suddenly. Calculate the temperature of escaping air. Given initial room temperature is 15^(@)C and gamma for air is 1.4 .

    A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

    Air (gamma = 1.4 ) is pumped at 20atm pressure in a motor tyre at 20^@C . If the tyre suddenly bursts, what would be the temperature of the air coming out of the tyre. Neglect any mixing with the atmoshpheric air.

    Dry air at 15^0 C and 10 atm is suddenly released at atmospheric pressure. Find the final temperature of the air [C_p / C_v = 1.41] .

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