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A magnetic flux through a stationary loo...

A magnetic flux through a stationary loop with a resistance `R` varies during the time interval `tau` as `phi=at(tau-t)`. Find the amount of the generated in the loop during that time

Text Solution

Verified by Experts

The correct Answer is:
`(a^(2)tau^(3))/(3R)`
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A magentic flux through a statinary loop with a resistance R varies during the tiem interval tau as Phi = at (tau - t) . Find the amount of heat generated in the loop during that time. The inductance of the loop is to be neglected.

The magnetic flux through a stationary loop with a resistanoe R varies during interval of time T as phi= at (T- t). If the heat generated during this time, neglecting the inductance of the loop, is (a^(2) T^(3))/(p R) , then find p .

Knowledge Check

  • The magnetic flux through a stationary loop with resistance R varies during interval of time T as phi = at (T – t). The heat generated during this time neglecting the inductance of loop will be

    A
    `(a^(2)T^(3))/(3R)`
    B
    `(a^(2)T^(2))/(3R)`
    C
    `(a^(2)T)/(3R)`
    D
    `(a^(2)T^(3))/(R)`

  • The magnetic flux through a circuit of resistance R changes by an amount Delta phi in a time Delta t . Then the total quantity of electric charge Q that passes any point in the circuit during the time Delta t is represented by

    A
    `Q=(1)/(R ).(Delta phi)/(Delta t)`
    B
    `Q=(Delta phi)/(R )`
    C
    `Q=(Delta phi)/(Delta t)`
    D
    `Q=R.(Delta phi)/(Delta t)`

  • The magnetic flux through a circuit of resistance R changes by an amount Delta phi in a time Delta t . Then the total quantity of electric charge Q that passes any point in the circuit during the time Delta t is represented by

    A
    `Q= (1)/(R)(Delta phi)/(Delta t)`
    B
    `Q= (Delta phi)/(R)`
    C
    `Q= (Delta phi)/(Delta t)`
    D
    `Q= R. (Delta phi)/(Delta t)`

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