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If y = sin^(-1) (19/20x) + cos^(-1)(19/2...

If `y = sin^(-1) (19/20x) + cos^(-1)(19/20x)`, then `(dy)/(dx)=`

A

0

B

1

C

`-1`

D

2

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If y = sin[cos^(-1){sin(cos^(-1) x)}], "then" (dy)/(dx)" at x" = (1)/(2)

    A
    0
    B
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    D
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  • If y=(sin^(-1)x-cos^(-1)x)/(sin^(-1)x+cos^(-1)x)," then "(dy)/(dx)=

    A
    `(4)/(pisqrt(1-x^(2)))`
    B
    `(2)/(pisqrt(1-x^(2)))`
    C
    `(1)/(pisqrt(1-x^(2)))`
    D
    `(pi)/(4sqrt(1-x^(2)))`
  • If y=sin(2 cos^(-1)x),"then " dy/dx=

    A
    ` (2cos (2cos ^(-1) x))/( sqrt(1-x^(2)))`
    B
    ` (-2cos (2cos ^(-1) x))/( sqrt(1-x^(2)))`
    C
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    D
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