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TARGET PUBLICATION-DIFFERENTIATION -DERIVATIVE OF COMPOSITE FUNCTIONS
- The derivative of sqrt(sqrt(x)+1) is
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- If y=sec x^(@), then (dy)/(dx)=
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- [d/(dx)(10^(x tanx))] is equal to
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- If y=e^(x^(2)/(1+x^(2))), then (dy)/(dx)=
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- If y=sqrt(u) ,u=(3-2v)v and v=x^(2), then (dy)/(dx)=
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- If y ( cos x ^(2))^(2) , "then" (dy)/(dx) is equal to
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- If y=(tan x + cot x)/(tan x - cot x), then (dy)/(dx)=
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- If y=log(sqrt(x) + sqrt(x-a)), then (dy)/(dx) is
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- d/(dx)[log ((cos(e^(x))))]=
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- d/(dx)[e^(ax)/(sin(bx+c))]=
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- If y=sin(sqrt(sinx+cosx)), find (dy)/(dx).
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- (d)/(dx)sqrt(sec^(2)x+cosec^(2)x)=
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- If y=(x cot^(3)x)^(3/2), then (dy)/(dx)=
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- If y=sqrt((1+tanx)/(1-tanx))," then: "(dy)/(dx)=
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- If y=log[tan(pi/4 +x/2)]),then (dy)/(dx) is
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- If y=log sqrt((1-cos x)/(1+ cos x)), then (dy)/(dx) is
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- d/(dx)[log{e^x ((x-2)/(x+2))^(3/4)}]=
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- If : f(x)=(1)/(sqrt(x^(2)+a^(2))+sqrt(x^(2)+b^(2)))" then: "f'(x)=
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- (d)/(dx)[log(sqrt((1+sinx)/(1-sinx)))]=
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- If y=x/2 sqrt(a^(2)+x^(2)) +a^(2)/2 log(x+sqrt(x^(2)+a^(2))), then (dy...
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