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Magnetic force on a charged particle is ...

Magnetic force on a charged particle is given by `vec F_(m) = q(vec(v) xx vec(B))` and electrostatic force `vec F_(e) = q vec (E)`. A particle having charge q = 1C and mass 1 kg is released from rest at origin. There are electric and magnetic field given by `vec(E) = (10 hat(i)) N//C for x = 1.8 m` and `vec(B) = -(5 hat(k)) T` for `1.8 m le x le 2.4 m`
A screen is placed parallel to y-z plane at `x = 3 m`. Neglect gravity forces.
The speed with which the particle will collide the screen is

A

3

B

6

C

9

D

12

Text Solution

Verified by Experts

The correct Answer is:
b
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Knowledge Check

  • Magnetic force on a charged particle is given by vec F_(m) = q(vec(v) xx vec(B)) and electrostatic force vec F_(e) = q vec (E) . A particle having charge q = 1C and mass 1 kg is released from rest at origin. There are electric and magnetic field given by vec(E) = (10 hat(i)) N//C for x = 1.8 m and vec(B) = -(5 hat(k)) T for 1.8 m le x le 2.4 m A screen is placed parallel to y-z plane at x = 3 m . Neglect gravity forces. Time after which the particle will collide the screen is (in seconds)

    A
    `1/5 (3+(pi)/(6)+(1)/(sqrt(3)))`
    B
    `1/5 (6+(pi)/(3)+(sqrt(3)))`
    C
    `1/3 (5+(pi)/(6)+(1)/(sqrt(3)))`
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    `1/5 (6+(pi)/(18)+(sqrt(3)))`

  • Magnetic force on a charged particle is given by vec F_(m) = q(vec(v) xx vec(B)) and electrostatic force vec F_(e) = q vec (E) . A particle having charge q = 1C and mass 1 kg is released from rest at origin. There are electric and magnetic field given by vec(E) = (10 hat(i)) N//C for x = 1.8 m and vec(B) = -(5 hat(k)) T for 1.8 m le x le 2.4 m A screen is placed parallel to y-z plane at x = 3 m . Neglect gravity forces. y-coordinate of particle where it collides with screen (in meters) is

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    `(0.6(sqrt(3)-1))/(sqrt(3))`
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    always zero
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    zero, if `vec(B) and vec(V)` are parallel
    D
    zero, if `vec(B) and vec(V)` are inclined at `45^(@)`

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