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Passage I) In simple harmonic motion for...

Passage I) In simple harmonic motion force acting on a particle is given as `F=-4x`, total mechanical energy of the particle is 10 J and amplitude of oscillations is 2m, At time t=0 acceleration of the particle is `-16m/s^(2)`. Mass of the particle is 0.5 kg.
Potential energy of the particle at mean position is

A

10 J

B

8 J

C

6 J

D

2 J

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Passage I) In simple harmonic motion force acting on a particle is given as F=-4x , total mechanical energy of the particle is 10 J and amplitude of oscillations is 2m, At time t=0 acceleration of the particle is -16m/s^(2) . Mass of the particle is 0.5 kg. At x=+1m, potential energy and kinetic energy of the particle are

    A
    2 J and 8 J
    B
    8 J and 2 J
    C
    6 J and 4 J
    D
    4 J and 6 J
  • Passage I) In simple harmonic motion force acting on a particle is given as F=-4x , total mechanical energy of the particle is 10 J and amplitude of oscillations is 2m, At time t=0 acceleration of the particle is -16m/s^(2) . Mass of the particle is 0.5 kg. Displacement time equation equation of the particle is

    A
    `x=2sin2t`
    B
    `x= 2sin4t`
    C
    `x=2cos2t`
    D
    None of these
  • A particle of mass m executing S.H.M. about its mean position. The total energy of the particle at given instant is

    A
    `(pi^2mA^2)/(T^2)`
    B
    `(2pi^2mA^2)/(T^2)`
    C
    `(4pi^2mA^2)/(T^2)`
    D
    `(8pimA^2)/(T^2)`
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