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A particle is executing SHM with amplitu...

A particle is executing SHM with amplitude A. At displacement `x=(-A/4)`, force acting on the particle is F, potential energy of the particle is U, velocity of particle is v and kinetic energy is K. Assuming potential energyh to be zero at mean position. At displacement x=A/2

A

Force acting on the particle will be 2F

B

potential energy of the particle will be 4U.

C

velocity of particle must be `sqrt(4/5)`v

D

kinetic energy of particle will be 0.8 K

Text Solution

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The correct Answer is:
B, D
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Knowledge Check

  • A particle executing SHM with an amplitude A. The displacement of the particle when its potential energy is half of its total energy is

    A
    `(A)/(sqrt(2))`
    B
    `(A)/(2)`
    C
    `(A)/(4)`
    D
    `(A)/(3)`

  • A particle is executing SHM with an amplitude 4 cm. the displacment at which its energy is half kinetic and half potential is

    A
    1 cm
    B
    `2^(1//2) cm`
    C
    `2 cm`
    D
    `2(2)^(1//2) cm`

  • If x, F and U denote the displacement force acting on and potential energy of a particle:

    A
    `U=F`
    B
    `F=+(dU)/(dx)`
    C
    `F=-(dU)/(dx)`
    D
    `F=1/x((dU)/(dx))`

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