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What happen when a solution of potassium...

What happen when a solution of potassium chromate is treated with an excess of dil. Nitic acid?

A

`Cr_(2)O_(7)^(2-)` and `H_(2)O` are formed

B

`CrO_(4)^(2-)` is reduced to `+3` state of Cr

C

`CrO_(4)^(2-)` is oxidized to `+7` state of Cr

D

`Cr^(3+)` and `Cr_(2)O_(7)^(2-)` are formed

Text Solution

Verified by Experts

The correct Answer is:
A
(a) When a solution of potassium chromate is treated with an excess of dilute nitric acid. Potassium dichromate and `H_(2)O` are formed.
`2K_(2)CrO_(4)+2HNO_(3)rarrK_(2)Cr_(2)O_(7)+2KNO_(3)+H_(2)O`
Hence `Cr_(2)O_(7)^(-) ` and `H_(2)O` are formed
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Knowledge Check

  • What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

    A
    `Cr_(2)O_(7)^(2-) and H_(2)O` are formed
    B
    `CrO_(4)^(2-) ` is reduced to +3 state of Cr
    C
    `CrO_(4)^(2-)` is oxidized to +7 state of Cr
    D
    `Cr^(3+) and Cr_(2)O_(7)^(2-)` are formed

  • What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

    A
    `Cr_(2)O_(7)^(2-)` and `H_(2)O` are formed
    B
    `CrO_(4)^(2-)` is reduced to + 3 state of Cr
    C
    `CrO_(4)^(2-)` is oxidized to + 7 state of Cr
    D
    `Cr^(3+)` and `Cr_(2)O_(7)^(2-)` are formed

  • What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid ?

    A
    `Cr_(2)O_(7)^(2-)` and `H_(2)O` are formed
    B
    `CrO_(4)^(2-)` is reduced to `+3` state of Cr
    C
    `CrO_(4)^(2-)` is oxidized to `+7` state of Cr
    D
    `Cr^(3+)` and `Cr_(2)O_(7)^(2-)` are formed