The total energy of a revolving satellite around the earth is `-KJ`. The minimum energy required to throw it out of earth's gravitational fields is

Options

A. `KJ`
B. `(K)/(2)J`
C. `2KJ`
D. None of these

Explanation

To find the minimum energy required to throw a satellite out of the Earth's gravitational field, we can follow these steps:

### Step 1: Understand the Total Energy of the Satellite
The total energy (E) of a satellite in orbit is given as \( E = -K \) joules. This negative value indicates that the satellite is bound to the Earth due to gravitational potential energy.

### Step 2: Define the Final Energy When the Satellite is Thrown Out
When the satellite is thrown out of the Earth's gravitational field, we want it to have enough energy to escape. At this point, we can assume that its total energy will be zero (E_final = 0) because it will be at rest at infinity where gravitational effects are negligible.

### Step 3: Set Up the Energy Equation
The total energy of the satellite before it is thrown out is the sum of its initial energy and the energy we need to provide (let's call this \( K' \)):
\[ E_{initial} + K' = E_{final} \]
Substituting the known values:
\[ -K + K' = 0 \]

### Step 4: Solve for the Minimum Energy Required
Rearranging the equation gives us:
\[ K' = K \]
This means the minimum energy required to throw the satellite out of the Earth's gravitational field is equal to \( K \) joules.

### Conclusion
Thus, the minimum energy required to throw the satellite out of Earth's gravitational field is \( K \) joules.

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