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The hybridisation of carbon atoms in C -...

The hybridisation of carbon atoms in C - C single bond is `HC-=C-CH=CH_(2)` is

A

`Sp^(3)-Sp^(3)`

B

`Sp^(2)-Sp^(3)`

C

`Sp-Sp^(2)`

D

`Sp^(3)-Sp`

Text Solution

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The correct Answer is:
To determine the hybridization of the carbon atoms in the compound HC≡C-CH=CH₂, we will analyze the structure step by step. ### Step 1: Identify the structure The compound HC≡C-CH=CH₂ can be broken down as follows: - The first carbon (C1) is connected to a hydrogen (H) and has a triple bond with the second carbon (C2). - The second carbon (C2) is connected to the first carbon (C1) via a triple bond and to the third carbon (C3) via a single bond. - The third carbon (C3) is connected to the second carbon (C2) via a single bond and has a double bond with the fourth carbon (C4). - The fourth carbon (C4) is connected to the third carbon (C3) via a double bond and has two hydrogen atoms attached to it. ### Step 2: Analyze the hybridization of each carbon 1. **Carbon C1 (HC≡C)**: - C1 has 4 valence electrons. - It forms a triple bond with C2 (which consists of 1 sigma bond and 2 pi bonds) and has 1 hydrogen atom attached. - The steric number for C1 is 1 (from the sigma bond with C2) + 0 (lone pairs) = 1. - Therefore, the hybridization of C1 is **sp**. 2. **Carbon C2 (C≡C-CH)**: - C2 also has 4 valence electrons. - It forms a triple bond with C1 (1 sigma bond, 2 pi bonds) and a single bond with C3. - The steric number for C2 is 1 (from the sigma bond with C1) + 1 (from the single bond with C3) + 0 (lone pairs) = 2. - Therefore, the hybridization of C2 is **sp**. 3. **Carbon C3 (CH=CH₂)**: - C3 has 4 valence electrons. - It forms a single bond with C2 and a double bond with C4 (which consists of 1 sigma bond and 1 pi bond). - The steric number for C3 is 1 (from the single bond with C2) + 1 (from the double bond with C4) + 0 (lone pairs) = 2. - Therefore, the hybridization of C3 is **sp²**. 4. **Carbon C4 (CH₂)**: - C4 has 4 valence electrons. - It forms a double bond with C3 and has 2 hydrogen atoms attached. - The steric number for C4 is 1 (from the double bond with C3) + 2 (from the two hydrogen atoms) + 0 (lone pairs) = 3. - Therefore, the hybridization of C4 is **sp²**. ### Conclusion - C1: sp hybridization - C2: sp hybridization - C3: sp² hybridization - C4: sp² hybridization ### Final Answer The hybridization of the carbon atoms in HC≡C-CH=CH₂ is: - C1: sp - C2: sp - C3: sp² - C4: sp²
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The hybridization of carbon atom in C-C single bond of HC-=C-CH=CH_2 is sp^3-sp^2 sp^2-sp^3 sp-sp^2 sp^3-sp^3

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Knowledge Check

  • The hybridisation of carbon atoms in C-C single bond of HC-=C-CH=CH=CH_(2)

    A
    `sp^(3)-sp^(3)`
    B
    `sp^(2)-sp^(3)`
    C
    `sp-sp^(2)`
    D
    `sp^(3)-sp`
  • The hybridization of carbon atoms in the C--C single bond of HC-=C-CH=CH_2 is

    A
    `sp^3-sp^3`
    B
    `sp^2-sp^3`
    C
    `sp-sp^2`
    D
    `sp^3-sp`
  • The hybridisation of carbons involved in C-C single bond in CH-=C-CH = CH_2 is

    A
    `sp^3 - sp^2`
    B
    `sp^3 -sp^3`
    C
    `sp - sp^2`
    D
    `sp- sp^3`
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